微信跳一跳小游戏python脚本

def screenshot():
 cmd = 'adb shell screencap -p /sdcard/1.png'
 os.system(cmd)
 cmd = 'adb pull /sdcard/1.png'
 os.system(cmd)

#开始查找棋子的坐标，从start_y开始据目测棋子不会位于屏幕底部1/3处
for i in range(start_y, int(height * 2 / 3)):
 for j in range(border_x, width - border_x): #删除周围空白部分，加快程序运行速度
 next_point = im[j,i]
 # 根据棋子的颜色判断，求所有点的和然后求平均值
 if (50 < next_point[0] < 60) and (53 <next_point[1] < 63) and (95 < next_point[2] < 110):
 x1_temp += j #点求和
 x1_num += 1 #点的个数
 y1_max = max(i, y1_max)

if not all((x1_temp,x1_num)):
 return 0,0,0,0
x1 = x1_temp / x1_num
y1 = y1_max - piece_height/2 # 棋子Y轴坐标上移到底盘高度的一半

#查找下一个棋盘的位置
for i in range(start_y, height * 2 / 3):
 start_point = im[0, i]
 if x2 or y2:
 break
 x2_temp = 0
 x2_num = 0
 for j in range(width):
 next_point = im[j,i]

 if abs(j - x1) < body_width:
 continue

 # 棋盘为圆
 if abs(next_point[0] - start_point[0]) + abs(next_point[1] - start_point[1]) + abs(next_point[2] - start_point[2]) > 10:
 x2_temp += j
 x2_num += 1
 if x2_temp:
 x2 = x2_temp / x2_num
# 按实际的角度通过tan值来算计算下一个棋盘的中心点的Y轴坐标
y2 = y1 - abs(x2 - x1) * abs(sample_y1 - sample_y2) / abs(sample_x1 - sample_x2)

if not all((x2, y2)):
 return 0, 0, 0, 0

#跳到下一个棋盘
def jump(distance):
 press_time = distance * press
 press_time = max(press_time, 200) # 设置最小的按压时间位200ms
 press_time = int(press_time)
 cmd = 'adb shell input swipe {} {} {} {} {}'.format(swipe_x1, swipe_y1, swipe_x2, swipe_y2, press_time)
 print(cmd)
 os.system(cmd)