python中退出多层循环的方法

# 第一种嵌套形式
a = [[1, 2, 3], [5, 5, 6], [7, 8, 9]]
# init_i = 0
# init_j = 0
flag = True
for i in range(3):
  for j in range(3):
    # print(i, j)
    if a[i][j] == 5:
      flag = False
      init_i = i
      init_j = j
      break
  if not flag:
    break
print(init_i, init_j)
print(i, j)

# 第二种嵌套形式
flag = True
while flag:
  for i in range(10):
    print(x)
    flag = False
    break

def test():
  while True:
    for x in range(10):
      print(x)
      return
test()

a = [[1, 2, 3], [5, 5, 6], [7, 8, 9]]
init_i = 0
init_j = 0
flag = True
for i in range(3):
  for j in range(3):
    # print(i, j)
    if a[i][j] == 5:
      flag = False
      init_i = i
      init_j = j
      break
  else:
    continue
  break
  # if not flag:
  #   break
print(init_i, init_j)
print(i, j)

while True:
  for x in range(4):
    print(x)
    if x == 2:
      break
  else:
    print("未执行")
    continue
  break

class getoutofloop(Exception): pass
try:
  for i in range(5):
    for j in range(5):
      for k in range(5):
        if i == j == k == 3:
          raise getoutofloop()
        else:
          print i, '----', j, '----', k
except getoutofloop:
  pass

def test():
  for i in range(5):
    for j in range(5):
      for k in range(5):
        if i == j == k == 3:
          return
        else:
          print i, '----', j, '----', k
test()

for i in range(5):
  for j in range(5):
    for k in range(5):
      if i == j == k == 3:
        break
      else:
        print i, '----', j, '----', k
    else: continue
    break
  else: continue
  break