Go语言字符串高效拼接的实现

var s string
s+="昵称"+":"+"志强1224"+"\n"
s+="联系方式QQ"+":"+"354662600"+"\n"
fmt.Println(s)

fmt.Sprint("昵称",":","志强1224","\n","联系方式QQ",":","354662600")

s:=[]string{"昵称",":","志强1224","\n","联系方式QQ",":","354662600"}
fmt.Println(strings.Join(s,""))

var b bytes.Buffer
b.WriteString("昵称")
b.WriteString(":")
b.WriteString("志强1224")
b.WriteString("\n")
b.WriteString("联系方式QQ")
b.WriteString(":")
b.WriteString("354662600")
b.WriteString("\n")
fmt.Println(b.String())

var b strings.Builder
b.WriteString("昵称")
b.WriteString(":")
b.WriteString("志强1224")
b.WriteString("\n")
b.WriteString("联系方式QQ")
b.WriteString(":")
b.WriteString("354662600")
b.WriteString("\n")
fmt.Println(b.String())

func StringPlus(p []string) string{
  var s string
  l:=len(p)
  for i:=0;i<l;i++{
   s+=p[i]
  }
  return s
}

func StringFmt(p []interface{}) string{
  return fmt.Sprint(p...)
}

func StringJoin(p []string) string{
  return strings.Join(p,"")
}

func StringBuffer(p []string) string {
  var b bytes.Buffer
  l:=len(p)
  for i:=0;i<l;i++{
   b.WriteString(p[i])
  }
  return b.String()
}

func StringBuilder(p []string) string {
  var b strings.Builder
  l:=len(p)
  for i:=0;i<l;i++{
   b.WriteString(p[i])
  }
  return b.String()
}