python 实现二维列表转置

def transpose(self, matrix):
    new_matrix = []
    for i in range(len(matrix[0])):
      matrix1 = []
      for j in range(len(matrix)):
        matrix1.append(matrix[j][i])
      new_matrix.append(matrix1)
    return new_matrix

def transpose(self, matrix):
    new_matrix = []
    for i in range(len(matrix[0])):
      matrix1 = []
      for j in range(len(matrix)):
        matrix1.append(matrix[j][i])
      new_matrix.append(matrix1)
    return new_matrix[::-1]

# -*- coding:utf-8 -*-
class Solution:
  # matrix类型为二维列表，需要返回列表
  # matrix应该是列表组成的列表
  # 去掉首行，然后逆时针转置
  def printMatrix(self, matrix):
    # write code here
    result = []
    while matrix:
      result.extend(matrix.pop(0))
      if not matrix:
        break
      matrix = self.transpose(matrix)
    return result
  # 转置
  def transpose(self, matrix):
    new_matrix = []
    for i in range(len(matrix[0])):
      matrix1 = []
      for j in range(len(matrix)):
        matrix1.append(matrix[j][i])
      new_matrix.append(matrix1)
    return new_matrix[::-1]