python 实现以相同规律打乱多组数据

import random
seed =50
x_batch, y_batch,start_num = train_load_order_sharp_5_9(image_list, num, start_num,length)
#加载我所有的数据,这里想x_batch,Y_batch是list的格式,要注意
random.seed(seed)
random.shuffle(x_batch)
random.seed(seed)#一定得重复在写一遍,和上面的seed要相同,不然y_batch和x_batch打乱顺序会不一样
random.shuffle(y_batch)

from random import shuffle
shuffle_data=True
if shuffle_data:
  c = list(zip(x_batch,y_batch))
  shuffle(c)
  x_batch,y_batch = zip(*c)

>>> a=[1,2,3,4]
>>> b=[11,22,33,44]
>>> c=list(zip(a,b))
>>> shuffle(c)
>>> a,b = zip(*c)
>>> a
(2, 4, 3, 1)
>>> b
(22, 44, 33, 11)
#这里就让a,b以相同的规律被打乱

x = [1,2,3,4,5,6]
random.shuffle(x)
print(x)

def shuffle(self, x, random=None):
"""Shuffle list x in place, and return None.

"""
if random is None:
randbelow = self._randbelow
for i in reversed(range(1, len(x))):
# pick an element in x[:i+1] with which to exchange x[i]
j = randbelow(i + 1)
x[i], x[j] = x[j], x[i]
else:
_int = int
for i in reversed(range(1, len(x))):
# pick an element in x[:i+1] with which to exchange x[i]
j = _int(random() * (i + 1))
x[i], x[j] = x[j], x[i]