在service层注入mapper时报空指针的解决

@RunWith(SpringRunner.class)
@SpringBootTest(classes = SpringBoot_Run.class)
@ContextConfiguration(locations = { "classpath:mybatis/mappers/RevMapper.xml" })
public class TestTransaction {
 @Autowired
 RevMapper remapper;
 @Test
 public void testInsert() {
  ReData data = new ReData();
  data.setReTime(new Date()).setSeID("fdewfcdsfdssdfdsf").setSendDate(new Date());
  remapper.insertObject(data);
 }

public class ReService {
 
 @Autowired
 private RevMapper reMapper;
 private Socket socket=null;
 private BufferedReader br=null;
 private PrintWriter pw=null;
 public void recevice() {
  try {
    //创建服务器,并开放3081端口
      ServerSocket serv

@SpringBootApplication(exclude=DataSourceAutoConfiguration.class)
@MapperScan(“cn.yungtay.mapper”)
public class SpringBoot_Run {
public static void main(String[] args) {
 SpringApplication.run(SpringBoot_Run.class, args);
 ReMapper re=new ReMapper();
 re.receive;
}
}

@Service
public class ReService implements ApplicationRunner{
@Autowired
private RevMapper reMapper;
private Socket socket=null;
。。。。。。。。。。。。。
@Override
public void run(ApplicationArguments args) throws Exception {
 // TODO Auto-generated method stub
 你所需要启动的方法XXXXXXXX
}

@Autowired
UserMapper usermapper; 

ApplicationContext  ac = new ClassPathXmlApplicationContext("classpath:applicationContext.xml");
usermapper = (UserMapper) ac.getBean("UserMapper");
usermapper.deleteAllCookies();

@Repository(value="UserMapper")
public interface UserMapper {
public List<User> selectByExample(@Param("username1")String username,@Param("password")String password);
public int insertToken(@Param("username1")String username,@Param("token")String token);
public String checkToken(String token);
public int logout(@Param("username1")String username,@Param("token")String token);
public int deleteAllCookies();
}