Python如何将给定字符串中的大写英文字母按以下对应规则替换

inp = input()
dist = ['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M',
        'N' 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']
for i in inp:
    if i in dist:
        index = dist.index(i)
        inp = inp.replace(i, dist[-index - 1])
print(inp)

str = input()
for i in str:
    num = ord(i)  # 得到ASCII码
    if (65 <= num <= 90):  # 如果是大写字母
        str = str.replace(i, chr(155 - num))
print(str)

str = input()
def replace(str):
    for i in str:
        num = ord(i)  # 得到ASCII码
        if (num >= 65 & num <= 90):  # 如果是大写字母
            i = chr(155 - num)
    return str
replace(str)
print(str)

str = input()
for i in str:
    num = ord(i)  # 得到ASCII码
    if (65 <= num <= 90):  # 如果是大写字母
        str.replace(i, chr(155 - num))
print(str)

str = input()
newStr = ''
for i in str:
    num = ord(i)  # 得到ASCII码
    if (65 <= num <= 90):  # 如果是大写字母
        i = i.replace(i, chr(155 - num))
    newStr += i
print(newStr)

str = input()
newStr = ''
for i in str:
    if i.isupper():
        newStr += chr(155 - ord(i))
    else:
        newStr += i
        
print(newStr)

import string
n=eval(input())
s=string.ascii_uppercase
for i in s:
print(i,end='')
if (s.find(i)+1)%n==0:
print()