Python性能调优的十个小技巧总结

cube_numbers = []
  for n in range(0,10):
    if n % 2 == 1:
      cube_numbers.append(n**3)

cube_numbers = [n**3 for n in range(1,10) if n%2 == 1]

import requests
import re

def get_pages(link):
  pages_to_visit = []
  pages_to_visit.append(link)
  pattern = re.compile('https?')
  while pages_to_visit:
    current_page = pages_to_visit.pop(0)
    page = requests.get(current_page)
    for url in re.findall('<a href="([^" rel="external nofollow" ]+)">', str(page.content)):
      if url[0] == '/':
        url = current_page + url[1:]
      if pattern.match(url):
        pages_to_visit.append(url)
    # yield
    yield current_page
webpage = get_pages('http://www.example.com')
for result in webpage:
  print(result)

for name in member_list:
  print('{} is a member'.format(name))

a = [1,2,3,4,5]
b = [2,3,4,5,6]

overlaps = []
for x in a:
  for y in b:
    if x==y:
      overlaps.append(x)

print(overlaps)

a = [1,2,3,4,5]
b = [2,3,4,5,6]

overlaps = set(a) & set(b)

print(overlaps)

first_name, last_name, city = "Kevin", "Cunningham", "Brighton"

import itertools
iter = itertools.permutations(["Alice", "Bob", "Carol"])
list(iter)

import functools

@functools.lru_cache(maxsize=128)
def fibonacci(n):
  if n == 0:
    return 0
  elif n == 1:
    return 1
  return fibonacci(n - 1) + fibonacci(n-2)

def fibonacci(n):
  if n == 0: # There is no 0'th number
    return 0
  elif n == 1: # We define the first number as 1
    return 1
  return fibonacci(n - 1) + fibonacci(n-2)

import operator
my_list = [("Josh", "Grobin", "Singer"), ("Marco", "Polo", "General"), ("Ada", "Lovelace", "Scientist")]
my_list.sort(key=operator.itemgetter(0))
my_list