js实用技巧之去除数组或者对象里重复选项

javascriptCopy code
const arr = [1, 2, 3, 3, 4, 5, 5];
const uniqueArr = [...new Set(arr)];
console.log(uniqueArr); // [1, 2, 3, 4, 5]

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const arr = [1, 2, 3, 3, 4, 5, 5];
const uniqueArr = arr.filter((item, index) => {
  return arr.indexOf(item) === index;
});
console.log(uniqueArr); // [1, 2, 3, 4, 5]

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const arr = [1, 2, 3, 3, 4, 5, 5];
const uniqueArr = arr.reduce((prev, cur) => {
  if (!prev.includes(cur)) {
    prev.push(cur);
  }
  return prev;
}, []);
console.log(uniqueArr); // [1, 2, 3, 4, 5]

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const obj = {
  a: 1,
  b: 2,
  c: 3,
  d: 3,
  e: 4,
  f: 4
};
const uniqueObj = {};
for (const key in obj) {
  if (obj.hasOwnProperty(key)) {
    uniqueObj[obj[key]] = key;
  }
}
console.log(uniqueObj); // { '1': 'a', '2': 'b', '3': 'c', '4': 'e' }

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const obj = {
  a: 1,
  b: 2,
  c: 3,
  d: 3,
  e: 4,
  f: 4
};
const uniqueObj = Object.keys(obj).reduce((prev, key) => {
  const value = obj[key];
  if (!prev.hasOwnProperty(value)) {
    prev[value] = key;
  }
  return prev;
}, {});
console.log(uniqueObj); // { '1': 'a', '2': 'b', '3': 'c', '4': 'e' }