java获取两个List集合的交集代码示例

List<String> list1 = new ArrayList<>();
list1.add("apple");
list1.add("banana");
list1.add("orange");

List<String> list2 = new ArrayList<>();
list2.add("banana");
list2.add("orange");
list2.add("watermelon");

List<String> intersection = new ArrayList<>(list1);
intersection.retainAll(list2);
System.out.println(intersection);

private List<SysOrgUserRefModel> colationOrgUserData(List<SysOrgUserRefModel> saveEntities,List<WFGroupEntity> groupEntityList){
        // 拿出组织集合中的组织id集合
        List<String> groupList = groupEntityList.stream().map(WFGroupEntity::getId).collect(Collectors.toList());
        // 根据组织用户中的组织id与组织id集合比对，取相同的数据
        saveEntities = saveEntities.stream().filter(entity -> groupList.contains(CandidateDTO.newPostStr(entity.getOrgId()))).collect(Collectors.toList());
        return saveEntities;
    }

private List<SysOrgUserRefModel> colationOrgUserData(List<SysOrgUserRefModel> saveEntities,List<WFGroupEntity> groupEntityList){
        // 拿出组织集合中的组织id集合
        List<String> groupList = groupEntityList.stream().map(WFGroupEntity::getId).collect(Collectors.toList());
        // 根据组织用户中的组织id与组织id集合比对，取相同的数据
        saveEntities = saveEntities.stream().filter(entity -> !groupList.contains(CandidateDTO.newPostStr(entity.getOrgId()))).collect(Collectors.toList());
        return saveEntities;
    }