Python输入正负10进制,转4位16进制问题

#输入正负十进制，转4位16进制
def int_transform_4hex(intNums):
    if intNums < 0:  #如果是负数
        str_list_16nums = list(hex(intNums%65536))
        insert_num = 'f'
    else:           #如果是正数
        str_list_16nums = list(hex(intNums))
        insert_num = '0'
    #补位数
    if len(str_list_16nums) == 5:
        str_list_16nums.insert(2, insert_num)
    elif len(str_list_16nums) == 4:
        str_list_16nums.insert(2, insert_num)
        str_list_16nums.insert(2, insert_num)
    elif len(str_list_16nums) == 3:
        str_list_16nums.insert(2, insert_num)
        str_list_16nums.insert(2, insert_num)
        str_list_16nums.insert(2, insert_num)
    else:
        pass
    crc_data = "".join(str_list_16nums)  # 用""把数组的每一位结合起来  组成新的字符串
    hexNums = crc_data[2:4] + ' ' + crc_data[4:]
    return hexNums
if __name__ == '__main__':
    print(int_transform_4hex(200))
    print(int_transform_4hex(-200))

import struct
print(str(struct.pack("i",-15))[4:6])
print(hex(16**7 -15)[-2:])
print(hex(-15))
print()
print(str(struct.pack("i",-263))[4:6])
print(hex(16**7 -263)[-2:])
print(hex(-263))
print()
print(str(struct.pack("i",-10008))[4:6])
print(hex(16**7 -10008)[-2:])
print()

a = -99999
b = a % 256
print(b)
print(hex(b))